How do you delete a node from a binary search tree?
Delete function is used to delete the specified node from a binary search tree….Function:
- void deletion(Node*& root, int item)
- Node* parent = NULL;
- Node* cur = root;
- search(cur, item, parent);
- if (cur == NULL)
- if (cur->left == NULL && cur->right == NULL)
How is a binary search tree constructed?
Construct a Binary Search Tree
- Set the current node to be the root node of the tree.
- If the target value equals the key value for the current node, then the target value is found.
- If the target value is less than the key value for a node, make the current node the left child.
How do you add and remove an element from a binary search tree?
- Visit to the right subtree of the deleting node.
- Pluck the least value element called as inorder successor.
- Replace the deleting element with its inorder successor.
How do I remove a root node from AVL tree?
Solution: in this case, node B has balance factor -1. Deleting the node 60, disturbs the balance factor of the node 50 therefore, it needs to be R-1 rotated. The node C i.e. 45 becomes the root of the tree with the node B(40) and A(50) as its left and right child.
What are the rules to construct expression tree?
How to construct an expression tree?
- If we get an operand in the given expression, then push it in the stack.
- If an operator gets two values in the expression, then add in the expression tree as its child, and push them in the current node.
- Repeat Step-1 and Step-2 until we do not complete over the given expression.
What is a binary search tree How can you insert and delete an element in a BST explain using suitable examples?
Basic operations on a BST
- Create: creates an empty tree.
- Insert: insert a node in the tree.
- Search: Searches for a node in the tree.
- Delete: deletes a node from the tree.
- Inorder: in-order traversal of the tree.
- Preorder: pre-order traversal of the tree.
- Postorder: post-order traversal of the tree.
How do insertions and deletions differ in a BST?
Insertion: For inserting element as left child of 2, we have to traverse all elements. Therefore, insertion in binary tree has worst case complexity of O(n). Deletion: For deletion of element 2, we have to traverse all elements to find 2 (assuming we do breadth first traversal).